Solving Equations with Maximum Integers - Example 4

💡 Using the respective theorem, we can solve the given equation and find the solution.

🔍 The equation involves the maximum integer function and requires finding the value of x.

✅ To solve for x, we multiply all the terms by 2 and take the absolute value of the result.

🔑 The video discusses solving equations with absolute values.

🧩 The example equation is separated into two parts based on the definition 7.

📜 The solution is found using theorem 27 for one part and theorem 26 for the other part.

The video discusses the application of the respective theorems to solve equations.

The first equation uses theorem 27, while the second equation uses theorem 17.

The solutions to the equations are represented by real numbers.

📝 We have two equations: x ≤ -3 and x ≥ 7, which intersect at two intervals.

🔍 The first interval is -5 ≤ x ≤ -3, and the second interval is 7 ≤ x < 9.

✅ The solution is either x ≤ -3 or 7 ≤ x < 9, representing the intersection of the two intervals.

🔢 The video discusses equations involving the maximum integer function.

🔑 The solution to the equation is the union of two closed intervals.

📚 The intervals are: (-∞, -3] U [7, 9)